Challenge

Past

One concept, three rungs. Reaching rung 1 is the goal, so climb as far as you can.

Sticker Counts

simple dictionaries + looping

Rung 1Daily goal5 points

All the stickers

Write a function called total_stickers

You get a dictionary where each name points to how many stickers that child has, like {"amy": 3, "bob": 2}. Add up all the sticker counts and return the total. An empty dictionary gives 0.

Examples

Input	Output
{"amy": 3, "bob": 2}	5
{}	0
{"amy": 0}	0
{"amy": 10}	10

There are extra hidden tests, so make it work in general, not just for these.

Rung 2Bonus7 points

Who has the most

Write a function called who_has_most

Return the name of the child with the most stickers. If two children have the same amount, return the one that comes first in the dictionary. An empty dictionary returns None.

Examples

Input	Output
{"amy": 3, "bob": 5}	"bob"
{}	None
{"amy": 1}	"amy"
{"amy": 2, "bob": 2}	"amy"

There are extra hidden tests, so make it work in general, not just for these.

Rung 3Bonus10 points

Enough stickers

Write a function called at_least

Return a list of the names that have n stickers or more, keeping the order they appear in the dictionary. If nobody has that many, return an empty list.

Examples

Input	Output
{"amy": 3, "bob": 1}, 2	["amy"]
{}, 1	[]
{"amy": 5}, 5	["amy"]
{"amy": 1, "bob": 2}, 9	[]

There are extra hidden tests, so make it work in general, not just for these.

Finish Rung 1 and today counts. Rungs 2 and 3 are there if you want to push further.